(2y-1)(y^3+4y^2-8)=

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Solution for (2y-1)(y^3+4y^2-8)= equation:


Simplifying
(2y + -1)(y3 + 4y2 + -8) = 0

Reorder the terms:
(-1 + 2y)(y3 + 4y2 + -8) = 0

Reorder the terms:
(-1 + 2y)(-8 + 4y2 + y3) = 0

Multiply (-1 + 2y) * (-8 + 4y2 + y3)
(-1(-8 + 4y2 + y3) + 2y * (-8 + 4y2 + y3)) = 0
((-8 * -1 + 4y2 * -1 + y3 * -1) + 2y * (-8 + 4y2 + y3)) = 0
((8 + -4y2 + -1y3) + 2y * (-8 + 4y2 + y3)) = 0
(8 + -4y2 + -1y3 + (-8 * 2y + 4y2 * 2y + y3 * 2y)) = 0
(8 + -4y2 + -1y3 + (-16y + 8y3 + 2y4)) = 0

Reorder the terms:
(8 + -16y + -4y2 + -1y3 + 8y3 + 2y4) = 0

Combine like terms: -1y3 + 8y3 = 7y3
(8 + -16y + -4y2 + 7y3 + 2y4) = 0

Solving
8 + -16y + -4y2 + 7y3 + 2y4 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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